Me on this question ! an inequality is shown below: −np − 6 ≤ 3(c − 5) which of the following solves for n? n ≥ − the quantity 3 times c minus 21 all over p n ≥ − the quantity 3 times c minus 9 all over p n ≤ − the quantity 3 times c minus 21 all over p n ≤ − the quantity 3 times c minus 9 all over p

### Answers

The correct option is B) .

Step-by-step explanation:

Consider the provided inequality:

Now distribute 3 inside the parentheses.

Add 6 on both the side of the inequality:

Now, multiply both the sides by a negative sign and reverse the sign of inequality.

Divide both the sides of the inequality by p.

Now consider the provided options.

By observing the provided option it can be concluded that the correct option is B) .

-np - 6 < = 3c - 15

-np < = 3c - 15 + 6

-np < = 3c - 9

n > = (-3c + 9)/p

Step-by-step explanation:

We have been given the inequality

−np − 6 ≤ 3(c − 5)

We will solve for n

So, firstly we will shift 6 on right hand side of the inequality we get:

Now, we will open the parenthesis on right hand side of the inequality;

n ≥ − the quantity 3 times c minus 9 all over p

Step-by-step explanation:

To solve inequalities you should use the same method as to solve equalities.

1. First write down the inequality:

2. Solve the parentheses:

3. Pass the independent numbers to the right side of the inequality with opposite sign and do the mathematical operations:

4. Pass the p with the minus sign to the right side of the inequality, as p has the minus sign, the direction of the inequality changes:

c>=3 and n<0 and p<=(9-3 c)/n

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